2a^2-40a+100=a

Solution for 2a^2-40a+100=a equation:

2a^2-40a+100=a

We move all terms to the left:

2a^2-40a+100-(a)=0

We add all the numbers together, and all the variables

2a^2-41a+100=0

a = 2; b = -41; c = +100;
Δ = b2-4ac
Δ = -412-4·2·100
Δ = 881
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$a_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-41)-\sqrt{881}}{2*2}=\frac{41-\sqrt{881}}{4}
$
$a_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-41)+\sqrt{881}}{2*2}=\frac{41+\sqrt{881}}{4}
$